Clocked In Punched Out

given:
segment AD bisects segment BC
segment BC bisects segment AD

prove:
ΔABM and ΔDCM are congruent

1. segment AD bisects segment BC	1. given
2. segment AM ≅ segment DM	2. when a segment is bisected, the two resulting segments are congruent
3. segment BC bisects segment AD	3. given
4. segment BM ≅ segment CM	4. when a segment is bisected, the two resulting segments are congruent
5. ∠AMB ≅ ∠CMD	5. vertical angles are congruent
6. ΔABM ≅ ΔDCM	6. SAS postulate (2, 4, 5)

Still got it.

Anonymous 18 Feb 09 at 03:49

you must be asian.
i hated geometry…and proofs.

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Sweet Titty Bo Bitty 18 Feb 09 at 04:27

Niiiiiice. Geomking.

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hugo 18 Feb 09 at 15:46

oh my god you just brought me back to the 9th grade

i hate you

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John 18 Feb 09 at 20:35

Is this only for Euclidean geometry?

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1. Jon 19 Feb 09 at 01:06
  
  No, I can factor polynomials too.
  
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garkahar 21 Feb 09 at 21:59

the opposing angles is the only rule i remembered.

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Adam Riff™